Lattice Energy Born Haber Cycle
Calculations Using Born-Haber Cycles
- In one case a Born-Haber cycle has been constructed, information technology is possible to calculate the lattice energy (ΔHlatt ꝋ) past applying Hess'south law and rearranging:
ΔHf ꝋ = ΔHat ꝋ + ΔHat ꝋ + IE + EA + ΔHlatt ꝋ
- If we simplify this into three terms, this makes the equation easier to run into:
- ΔHlatt ꝋ
- ΔHf ꝋ
- ΔH1 ꝋ (the sum of all of the diverse enthalpy changes necessary to convert the elements in their standard states to gaseous ions)
- The simplified equation becomes
ΔHf ꝋ = ΔHane ꝋ + ΔHlatt ꝋ
So, if we rearrange to calculate the lattice free energy, the equation becomes
ΔHlatt ꝋ = ΔHf ꝋ - ΔH1 ꝋ
- When calculating the ΔHlatt ꝋ, all other necessary values will be given in the question
- A Born-Haber cycle could be used to calculate any stage in the cycle
- For example, you could exist given the lattice energy and asked to calculate the enthalpy change of formation of the ionic compound
- The principle would be exactly the same
- Work out the direct and indirect route of the cycle (the stage that you are being asked to summate will e'er be the direct road)
- Write out the equation in terms of enthalpy changes and rearrange if necessary to calculate the required value
- Recall: sometimes a value may need to exist doubled or halved, depending on the ionic solid involved
- For example, with MgCltwo the value for the first electron affinity of chlorine would need to exist doubled in the adding, because there are two moles of chlorine atoms
- Therefore, y'all are calculation 2 moles of electrons to 2 moles of chlorine atoms, to grade ii moles of Cl- ions
Worked example: Computing the lattice energy of KCl
Answer
- Stride i: The corresponding Built-in-Haber bicycle is:
- Step ii: Applying Hess' law, the lattice energy of KCl is:
ΔHlatt ꝋ = ΔHf ꝋ - ΔH1 ꝋ
ΔHlatt ꝋ = ΔHf ꝋ - [(ΔHat ꝋ G) + (ΔHat ꝋ Cl) + (IE1 K) + (EAane Cl)]
- Footstep 3: Substitute in the numbers:
ΔHlatt ꝋ = (-437) - [(+90) + (+122) + (+418) + (-349)] = -718 kJ mol-ane
Worked example: Calculating the lattice free energy of MgO
Reply
- Footstep 1: The corresponding Born-Haber cycle is:
- Step two: Applying Hess' law, the lattice energy of MgO is:
ΔHlatt ꝋ = ΔHf ꝋ - ΔH1 ꝋ
ΔHlatt ꝋ = ΔHf ꝋ - [(ΔHat ꝋ Mg) + (ΔHat ꝋ O) + (IEone Mg) + (IE2 Mg) + (EA1 O) + (EA2 O)]
- Step three: Substitute in the numbers:
ΔHlatt ꝋ = (-602) - [(+148) + (+248) + (+736) + (+1450) + (-142) + (+770)]
= -3812 kJ mol-ane
Test Tip
Make certain you use brackets when carrying out calculations using Born-Haber cycles equally you may forget a +/- sign which volition affect your final answer!
Lattice Energy Born Haber Cycle,
Source: https://www.savemyexams.co.uk/a-level/chemistry/cie/22/revision-notes/5-physical-chemistry-a-level-only/5-1-chemical-energetics-a-level-only/5-1-4-calculations-using-born-haber-cycles/
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